x+1(x^2+2)=0

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Solution for x+1(x^2+2)=0 equation:


Simplifying
x + 1(x2 + 2) = 0

Reorder the terms:
x + 1(2 + x2) = 0
x + (2 * 1 + x2 * 1) = 0
x + (2 + 1x2) = 0

Reorder the terms:
2 + x + 1x2 = 0

Solving
2 + x + 1x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + x + -2 + x2 = 0 + -2

Reorder the terms:
2 + -2 + x + x2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + x + x2 = 0 + -2
x + x2 = 0 + -2

Combine like terms: 0 + -2 = -2
x + x2 = -2

The x term is x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
x + 0.25 + x2 = -2 + 0.25

Reorder the terms:
0.25 + x + x2 = -2 + 0.25

Combine like terms: -2 + 0.25 = -1.75
0.25 + x + x2 = -1.75

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -1.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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